Problem 3.15 - The gage pressure at the coke surface is p...

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Problem 3.15 [Difficulty: 1] Given: Geometry of straw Find: Pressure just below the thumb Assumptions: (1) Coke is incompressible (2) Pressure variation within the air column is negligible (3) Coke has density of water Solution: Basic equation dp dy ρ g = or, for constant ρ Δ p ρ g h = where h is measured downwards This equation only applies in the 15 cm of coke in the straw - in the other 30 cm of air the pressure is essentially constant.
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Unformatted text preview: The gage pressure at the coke surface is p coke ρ g ⋅ h coke ⋅ = Hence, with h coke 15 − cm ⋅ = because h is measured downwards p coke 1000 − kg m 3 ⋅ 9.81 × m s 2 ⋅ 15 × cm ⋅ m 100 cm ⋅ × N s 2 ⋅ kg m ⋅ × kPa m 2 ⋅ 1000 N ⋅ × = p coke 1.471 − kPa ⋅ = gage p coke 99.9 kPa ⋅ =...
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