Problem 3.18 - Problem 3.18 [Difficulty: 2] Given: Data on...

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Problem 3.18 [Difficulty: 2] Given: Data on partitioned tank Find: Gage pressure of trapped air; pressure to make water and mercury levels equal Solution: The pressure difference is obtained from repeated application of Eq. 3.7, or in other words, from Eq. 3.8. Starting from the right air chamber p gage SG Hg ρ H2O × g × 3m 2.9 m () × ρ H2O g × 1 × m = p gage ρ H2O g × SG Hg 0.1 × m 1.0 m × = p gage 999 kg m 3 9.81 × m s 2 13.55 0.1 × m 1.0 m × Ns 2 kg m × = p gage 3.48 kPa
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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