Problem 3.18[Difficulty: 2]Given:Data on partitioned tankFind:Gage pressure of trapped air; pressure to make water and mercury levels equalSolution:The pressure difference is obtained from repeated application of Eq. 3.7, or in other words, from Eq. 3.8. Startingfrom the right air chamberpgageSGHgρH2O×g×3m⋅2.9m⋅−()×ρH2Og×1×m⋅−=pgageρH2Og×SGHg0.1×m⋅1.0m⋅−()×=pgage999kgm3⋅9.81×ms2⋅13.550.1×m⋅1.0m⋅−()×Ns2⋅kgm⋅×=pgage3.48 kPa
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