Problem 3.22 - Problem 3.22[Difficulty 2 Two fluid...

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Problem 3.22 [Difficulty: 2] Given: Two fluid manometer contains water and kerosene. With both tubes open to atmosphere, the difference in free surface elevations is known H o 20 mm = SG k 0.82 = (From Table A.1, App. A) Find: The elevation difference, H, between the free surfaces of the fluids when a gage pressure of 98.0 Pa is applied to the right tube. Solution: We will apply the hydrostatics equation. Governing Equations: dp dh ρ g = (Hydrostatic Pressure - h is positive downwards) ρ SG ρ water = (Definition of Specific Gravity) Assumptions: (1) Static liquid (2) Incompressible liquid When the gage pressure Δ p is applied to the right tube, the water in the right tube is displaced downward by a distance, l. The kerosene in the left tube is displaced upward by the same distance, l. Under the applied gage pressure Δ p, the elevation difference, H, is: h H A B l l H 0 H 1 A B Δ p HH o 2l + = Since points A and B are at the same elevation in the same fluid, their pressures are the same. Initially:
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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Problem 3.22 - Problem 3.22[Difficulty 2 Two fluid...

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