Problem 3.26

# Problem 3.26 - Problem 3.26[Difficulty 2 Given Water flow...

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Problem 3.26 [Difficulty: 2] Given: Water flow in an inclined pipe as shown. The pressure difference is measured with a two-fluid manometer L5 f t = h6 i n = SG Hg 13.55 = (From Table A.1, App. A) Find: Pressure difference between A and B Solution: We will apply the hydrostatics equations to this system. Governing Equations: dp dh ρ g = (Hydrostatic Pressure - h is positive downwards) ρ SG ρ water = (Definition of Specific Gravity) Assumptions: (1) Static liquid (2) Incompressible liquid (3) Gravity is constant Integrating the hydrostatic pressure equation we get: Δ p ρ g Δ h = Progressing through the manometer from A to B:
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## This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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