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Problem 3.27
[Difficulty: 2]
Given:
Data on fluid levels in a tank
Find:
Air pressure; new equilibrium level if opening appears
Solution:
Using Eq. 3.8, starting from the open side and working in gage pressure
p
air
ρ
H2O
g
×
SG
Hg
0.3
0.1
−
()
×
m
⋅
0.1 m
⋅
−
SG
Benzene
0.1
×
m
⋅
−
⎣
⎦
×
=
Using data from Table A.2
p
air
999
kg
m
3
⋅
9.81
×
m
s
2
⋅
13.55
0.2
×
m
⋅
0.1 m
⋅
−
0.879
0.1
×
m
⋅
−
×
Ns
2
⋅
kg m
⋅
×
=
p
air
24.7 kPa
⋅
=
To compute the new level of mercury in the manometer, assume the change in level from 0.3 m is an increase of
x
.
Then, because the
volume of mercury is constant, the tank mercury level will fall by distance (0.025/0.25)
2
x
.
Hence, the gage pressure at the bottom of the ta
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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