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Unformatted text preview: F = 2 w cos ( ) g h w a = Solving for h h 2 cos ( ) g a = For water = 72.8 mN/m and = 0 o (Table A.4), so a) Tube h 4 0.0728 N m 999 kg m 3 9.81 m s 2 0.005 m kg m N s 2 = h 5.94 10 3 m = h 5.94 mm = b) Parallel Plates h 2 0.0728 N m 999 kg m 3 9.81 m s 2 0.005 m kg m N s 2 = h 2.97 10 3 m = h 2.97 mm =...
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 Fall '07
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 Fluid Mechanics

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