Problem 3.40 - F = 2 w cos ( ) g h w a = Solving for h h 2...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Problem 3.40 [Difficulty: 2] Water Given: Water in a tube or between parallel plates Find: Height Δ h for each system Solution: a) Tube: A free-body vertical force analysis for the section of water height Δ h above the "free surface" in the tube, as shown in the figure, leads to F 0 = π D σ cos θ () ρ g Δ h π D 2 4 = Assumption: Neglect meniscus curvature for column height and volume calculations Solving for Δ h Δ h 4 σ cos θ () ρ g D = b) Parallel Plates: A free-body vertical force analysis for the section of water height Δ h above the "free surface" between plates arbitrary width w (similar to the figure above), leads to
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: F = 2 w cos ( ) g h w a = Solving for h h 2 cos ( ) g a = For water = 72.8 mN/m and = 0 o (Table A.4), so a) Tube h 4 0.0728 N m 999 kg m 3 9.81 m s 2 0.005 m kg m N s 2 = h 5.94 10 3 m = h 5.94 mm = b) Parallel Plates h 2 0.0728 N m 999 kg m 3 9.81 m s 2 0.005 m kg m N s 2 = h 2.97 10 3 m = h 2.97 mm =...
View Full Document

Ask a homework question - tutors are online