Problem 3.42

# Problem 3.42 - p SL = R= = 101 286.9 999 kPa J/kg.K kg/m3...

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p SL = 101 kPa R = 286.9 J/kg.K ρ = 999 kg/m 3 The temperature can be computed from the data in the figure. The pressures are then computed from the appropriate equation. From Table A.3 Agreement between calculated and tabulated data is very good (as it should be, considering the table data are also computed!) Atmospheric Pressure vs Elevation 0.00000 0.00001 0.00010 0.00100 0.01000 0.10000 1.00000 0 1 02 03 04 05 06 07 08 09 0 1 0 0 Elevation (km) Pressure Ratio p / SL Computed Table A.3

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z (km) T ( o C) T (K) p / p SL z (km) p / p SL 0.0 15.0 288.0 m = 1.000 0.0 1.000 2.0 2.0 275.00 0.0065 0.784 0.5 0.942 4.0 -11.0 262.0 (K/m) 0.608 1.0 0.887 6.0 -24.0 249.0 0.465 1.5 0.835 8.0 -37.0 236.0 0.351 2.0 0.785 11.0 -56.5 216.5 0.223 2.5 0.737 12.0 -56.5 216.5 T = const 0.190 3.0 0.692 14.0 -56.5 216.5 0.139 3.5 0.649 16.0 -56.5 216.5 0.101 4.0 0.609 18.0 -56.5 216.5 0.0738 4.5 0.570 20.1 -56.5 216.5 0.0530 5.0 0.533 22.0 -54.6 218.4 m = 0.0393 6.0 0.466 24.0 -52.6 220.4 -0.000991736 0.0288 7.0 0.406 26.0 -50.6 222.4 (K/m) 0.0211 8.0 0.352 28.0 -48.7 224.3 0.0155 9.0 0.304 30.0 -46.7 226.3 0.0115 10.0 0.262 32.2 -44.5 228.5 0.00824 11.0 0.224 34.0 -39.5 233.5 m = 0.00632 12.0 0.192 36.0 -33.9 239.1 -0.002781457 0.00473 13.0 0.164 38.0 -28.4 244.6 (K/m) 0.00356 14.0 0.140 40.0 -22.8 250.2 0.00270
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Problem 3.42 - p SL = R= = 101 286.9 999 kPa J/kg.K kg/m3...

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