Problem 3.46 - Problem 3.46 Given[Difficulty 3 Door located...

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Problem 3.46 [Difficulty: 3] Given: Door located in plane vertical wall of water tank as shown c p s a y y b a 1.5 m = b1 m = c1 m = Atmospheric pressure acts on outer surface of door. Find: Resultant force and line of action: (a) for (b) for p s p atm = p sg 0.3 atm = Plot F/Fo and y'/yc over range of ps/patm (Fo is force determined in (a), yc is y-ccordinate of door centroid). Solution: We will apply the hydrostatics equations to this system. Governing Equations: dp dy ρ g = (Hydrostatic Pressure - y is positive downwards) F R A p d = (Hydrostatic Force on door) y' F R A yp d = (First moment of force) Assumptions: (1) Static fluid (2) Incompressible fluid We will obtain a general expression for the force and line of action, and then simplify for parts (a) and (b). Since dp ρ g dh = it follows that pp s ρ g y + = Now because p atm acts on the outside of the door, p sg is the surface gage pressure: sg ρ g y + = F R A p d = c ca + y pb d = c + y
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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Problem 3.46 - Problem 3.46 Given[Difficulty 3 Door located...

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