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Unformatted text preview: ft 3 32.2 ft s 2 0.5 ft lbf s 2 slug ft ft 12 in 2 + = p B 0.416 psi = (gage) For point C p C p air2 SG Hg H2O g h 4 + = where h 4 10 in = h 4 0.833 ft = p C 0.416 lbf in 2 1.75 1.94 slug ft 3 32.2 ft s 2 0.833 ft lbf s 2 slug ft ft 12 in 2 + = p C 1.048 psi = (gage) For the second air cavity p air2 p C SG Hg H2O h 5 = where h 5 6 in = h 5 0.5 ft = p air2 1.048 lbf in 2 1.75 1.94 slug ft 3 32.2 ft s 2 0.5 ft lbf s 2 slug ft ft 12 in 2 = p air2 0.668 psi = (gage)...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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