Problem 3.51 - Problem 3.51 Given: Geometry of access port...

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Problem 3.51 [Difficulty: 2] F R dy a = 1.25 ft SG = 2.5 y b = 1 ft y’ w Given: Geometry of access port Find: Resultant force and location Solution: Basic equation F R A p d = dp dy ρ g = Σ M s y' F R = F R y d = A yp d = or, use computing equations F R p c A = y' y c I xx Ay c + = We will show both methods Assumptions: Static fluid; ρ = constant; p atm on other side F R A p d = A SG ρ g y d = but dA w dy = and w b y a = w b a y = Hence F R 0 a y SG ρ g y b a y d = 0 a y SG ρ g b a y 2 d = SG ρ g b a 2 3 = Alternatively F R p c A = and p c SG ρ g y c = SG ρ g 2 3 a = with A 1 2 a b = Hence F R SG ρ g b a 2 3 = For y' y' F R A d = 0 a y SG ρ g b a y 3
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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