Problem 3.56 - Problem 3.56 Given: Geometry of lock system...

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Problem 3.56 [Difficulty: 3] R y R x F R F n Given: Geometry of lock system Find: Force on gate; reactions at hinge Solution: Basic equation F R A p d = dp dh ρ g = or, use computing equation F R p c A = Assumptions: static fluid; ρ = constant; p atm on other side The force on each gate is the same as that on a rectangle of size hD = 10 m = and w W 2 cos 15 deg () = F R A p d = A ρ g y d = but dA w dy = Hence F R 0 h y ρ g y w d = ρ g w h 2 2 = Alternatively F R p c A = and F R p c A = ρ g y c A = ρ g h 2 h w = ρ g w h 2 2 = Using given data F R 1 2 1000 kg m 3 9.81 × m s 2 34 m 2 cos 15 deg × 10 m 2 × Ns 2 kg m × = F R 8.63 MN
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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