Problem 3.59

# Problem 3.59 - Problem 3.59[Difficulty 2 Given Door as...

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Problem 3.59 [Difficulty: 2] Given: Door as shown; Data from Example 3.6. Find: Force to keep door shut using the two seperate pressures method. Solution: We will apply the computing equations to this system. Governing Equations: F R p c A = y' y c I xx y c A + = I xx bL 3 12 = F 1 h 1 F 2 h 2 p 0 p 0 F 1 p 0 A = F 1 100 lbf ft 2 3 × ft 2 × ft = F 1 600lbf = x' 1 ft = z' 1.5 ft = F 2 p c A = ρ g h c L b = γ h c L b = F 2 100 lbf ft 3 1.5 × ft 3 × ft 2 × ft = F 2 900lbf = For the rectangular door I xx 1 12 b L 3 = h' 2 h c I xx h c + = h c 1 12 L 2 h c + = h' 2 1.5 m 1 12 3m () 2 1.5 m + = h' 2 2m = The free body diagram of the door is then
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## This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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