Problem 3.67 - Problem 3.67 Given Block hinged and floating...

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Problem 3.67 [Difficulty: 3] Given: Block hinged and floating Find: SG of the wood Solution: Basic equation dp dh ρ g = Σ M z 0 = Computing equations F R p c A = y' y c I xx Ay c + = Assumptions: Static fluid; ρ = constant; p atm on other side; no friction in hinge For incompressible fluid p ρ g h = where p is gage pressure and h is measured downwards The force on the vertical section is the same as that on a rectangle of height d and width L F 1 y’ F 2 Mg y x Hence F 1 p c A = ρ g y c A = ρ g d 2 d L = ρ g L d 2 2 = The location of this force is y' y c I xx c + = d 2 Ld 3 12 1 × 2 d × + = 2 3 d = The force on the horizontal section is due to constant pressure, and is at the centroid
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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