Problem 3.67[Difficulty: 3]Given:Block hinged and floatingFind:SG of the woodSolution:Basic equationdpdhρg⋅=ΣMz0=Computing equationsFRpcA⋅=y'ycIxxAyc⋅+=Assumptions:Static fluid; ρ= constant; patmon other side; no friction in hingeFor incompressible fluidpρg⋅h⋅=where p is gage pressure and h is measured downwardsThe force on the vertical section is the same as that on a rectangle of height d and width LF1y’ F2Mg y x HenceF1pcA⋅=ρg⋅yc⋅A⋅=ρg⋅d2⋅d⋅L⋅=ρg⋅L⋅d2⋅2=The location of this force isy'ycIxxc⋅+=d2Ld3⋅121⋅×2d×+=23d⋅=The force on the horizontal section is due to constant pressure, and is at the centroid
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.