Problem 3.79 - Problem 3.79 Given: Sphere with different...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Problem 3.79 [Difficulty: 4] Given: Sphere with different fluids on each side Find: Resultant force and direction Solution: The horizontal and vertical forces due to each fluid are treated separately. For each, the horizontal force is equivalent to that on a vertical flat plate; the vertical force is equivalent to the weight of fluid "above". For horizontal forces, the computing equation of Section 3-5 is F H p c A = where A is the area of the equivalent vertical plate. For vertical forces, the computing equation of Section 3-5 is F V ρ g V = where V is the volume of fluid above the curved surface. The data is For water ρ 999 kg m 3 = For the fluids SG 1 1.6 = SG 2 0.8 = For the weir D3 m = L6 m = (a) Horizontal Forces For fluid 1 (on the left) F H1 p c A = ρ 1 g D 2 D L = 1 2 SG 1 ρ g D 2 L = F H1 1 2 1.6 999 kg m 3 9.81 m s 2 3m () 2 6 m Ns 2 kg m = F H1 423 kN = For fluid 2 (on the right) F H2 p c A = ρ 2 g D 4 D 2 L = 1 8 SG 2 ρ g D 2 L = F H2 1 8 0.8 999 kg m 3 9.81 m s 2 2 6 m 2 kg m = F H2 52.9 kN = The resultant horizontal force is
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

Problem 3.79 - Problem 3.79 Given: Sphere with different...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online