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Problem 3.79

# Problem 3.79 - Problem 3.79 Given Sphere with different...

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Problem 3.79 [Difficulty: 4] Given: Sphere with different fluids on each side Find: Resultant force and direction Solution: The horizontal and vertical forces due to each fluid are treated separately. For each, the horizontal force is equivalent to that on a vertical flat plate; the vertical force is equivalent to the weight of fluid "above". For horizontal forces, the computing equation of Section 3-5 is F H p c A = where A is the area of the equivalent vertical plate. For vertical forces, the computing equation of Section 3-5 is F V ρ g V = where V is the volume of fluid above the curved surface. The data is For water ρ 999 kg m 3 = For the fluids SG 1 1.6 = SG 2 0.8 = For the weir D3 m = L6 m = (a) Horizontal Forces For fluid 1 (on the left) F H1 p c A = ρ 1 g D 2 D L = 1 2 SG 1 ρ g D 2 L = F H1 1 2 1.6 999 kg m 3 9.81 m s 2 3m () 2 6 m Ns 2 kg m = F H1 423 kN = For fluid 2 (on the right) F H2 p c A = ρ 2 g D 4 D 2 L = 1 8 SG 2 ρ g D 2 L = F H2 1 8 0.8 999 kg m 3 9.81 m s 2 2 6 m 2 kg m = F H2 52.9 kN = The resultant horizontal force is

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Problem 3.79 - Problem 3.79 Given Sphere with different...

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