Problem 3.86

# Problem 3.86 - Problem 3.86[Difficulty 4 Given Cylinder of...

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Problem 3.86 [Difficulty: 4] Given: Cylinder of mass M, length L, and radius R is hinged along its length and immersed in an incompressilble liquid to depth Find: General expression for the cylinder specific gravity as a function of α =H/R needed to hold the cylinder in equilibrium for α ranging from 0 to 1. Solution: We will apply the hydrostatics equations to this system. Governing Equations: dp dh ρ g = (Hydrostatic Pressure - h is positive downwards from free surface) dF H h θ dF V H = α R F v A y p d = (Vertical Hydrostatic Force) Σ M0 = (Rotational Equilibrium) Assumptions: (1) Static fluid (2) Incompressible fluid (3) Atmospheric pressure acts on free surface of the liquid. The moments caused by the hydrostatic force and the weight of the cylinder about the hinge need to balance each other. Integrating the hydrostatic pressure equation: p ρ g h = dF v dF cos θ () = pdA cos θ = ρ g h w R d θ cos θ = Now the depth to which the cylinder is submerged is H h

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## This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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Problem 3.86 - Problem 3.86[Difficulty 4 Given Cylinder of...

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