Problem 3.88

# Problem 3.88 - Problem 3.88 Given Geometry of glass...

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Problem 3.88 [Difficulty: 4] Given: Geometry of glass observation room Find: Resultant force and direction Assumptions: Water in aquarium is static and incompressible Solution: The x , y and z components of force due to the fluid are treated separately. For the x , y components, the horizontal force is equivalent to that on a vertical flat plate; for the z component, (vertical force) the force is equivalent to the weight of fluid above. For horizontal forces, the computing equation of Section 3-5 is F H p c A = where A is the area of the equivalent vertical plate. For the vertical force, the computing equation of Section 3-5 is F V ρ g V = where V is the volume of fluid above the curved surface. The data are For water ρ 1.94 slug ft 3 = For the fluid (Table A.2) SG 1.025 = For the aquarium R5 f t = H3 5 f t = (a) Horizontal Forces Consider the x component The center of pressure of the glass is y c H 4R 3 π = y c 32.88 ft = Hence F Hx p c A = SG ρ g y c () π R 2 4 = F Hx 1.025 1.94 × slug ft 3 32.2 × ft s 2 32.88 × ft π 5f t 2 4 × lbf s

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Problem 3.88 - Problem 3.88 Given Geometry of glass...

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