Problem 3.97 - Hence V F B 3 π ⋅ μ ⋅ d ⋅ = with μ...

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Problem *3.97 [Difficulty: 2] V F B W = Mg y F D Given: Data on hydrogen bubbles Find: Buoyancy force on bubble; terminal speed in water Solution: Basic equation F B ρ g V = ρ g π 6 d 3 = and Σ F y Ma y = Σ F y 0 = F B F D W = for terminal speed F B 1.94 slug ft 3 32.2 × ft s 2 π 6 × 0.001 in 1f t 12 in × 3 × lbf s 2 slug ft × = F B 1.89 10 11 × lbf = For terminal speed F B F D W 0 = F D 3 π μ V d = F B = where we have ignored W, the weight of the bubble (at
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Unformatted text preview: Hence V F B 3 π ⋅ μ ⋅ d ⋅ = with μ 2.10 10 5 − × lbf s ⋅ ft 2 ⋅ = from Table A.7 at 68 o F V 1.89 10 11 − × lbf ⋅ 1 3 π ⋅ × 1 2.10 10 5 − × × ft 2 lbf s ⋅ ⋅ 1 0.001 in ⋅ × 12 in ⋅ 1 ft ⋅ × = V 1.15 10 3 − × ft s ⋅ = V 0.825 in min ⋅ = As noted by Professor Kline in the film "Flow Visualization", bubbles rise slowly!...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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