Problem 4.19 - = The jet speeds are then V Q A total = V...

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Problem 4.19 [Difficulty: 1] Given: Data on flow through nozzles Find: Exit velocity in each jet; velocity in pipe Solution: Basic equation CS V A () 0 = Assumptions: 1) Steady flow 2) Incompressible flow 3) Uniform flow The given data is Q 2.2 gpm = d 1 32 in = n5 0 = (Number of nozzles) D 3 4 in = Area of each nozzle A π 4 d 2 = A 7.67 10 4 × in 2 = Area of the pipe A pipe π 4 D 2 = A pipe 0.442in 2 = Total area of nozzles A total nA = A total 0.0383in 2
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Unformatted text preview: = The jet speeds are then V Q A total = V 18.4 ft s = (Note that gal 231 in 3 = ) Then for the pipe flow CS V → A → ⋅ ( ) ∑ V pipe − A pipe ⋅ n V ⋅ A ⋅ + = = Hence V pipe V n A ⋅ A pipe ⋅ = V n ⋅ d D ⎛ ⎝ ⎞ ⎠ 2 ⋅ = V pipe 18.4 ft s ⋅ 50 × 1 32 3 4 ⎛ ⎜ ⎜ ⎜ ⎝ ⎞ ⎟ ⎠ 2 × = V pipe 1.60 ft s ⋅ =...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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