Problem 4.19

# Problem 4.19 - = The jet speeds are then V Q A total = V...

This preview shows page 1. Sign up to view the full content.

Problem 4.19 [Difficulty: 1] Given: Data on flow through nozzles Find: Exit velocity in each jet; velocity in pipe Solution: Basic equation CS V A ( ) 0 = Assumptions: 1) Steady flow 2) Incompressible flow 3) Uniform flow The given data is Q 2.2 gpm = d 1 32 in = n 50 = (Number of nozzles) D 3 4 in = Area of each nozzle A π 4 d 2 = A 7.67 10 4 × in 2 = Area of the pipe A pipe π 4 D 2 = A pipe 0.442in 2 = Total area of nozzles A total n A = A total 0.0383in 2 = The jet speeds are then
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: = The jet speeds are then V Q A total = V 18.4 ft s = (Note that gal 231 in 3 = ) Then for the pipe flow CS V → A → ⋅ ( ) ∑ V pipe − A pipe ⋅ n V ⋅ A ⋅ + = = Hence V pipe V n A ⋅ A pipe ⋅ = V n ⋅ d D ⎛ ⎝ ⎞ ⎠ 2 ⋅ = V pipe 18.4 ft s ⋅ 50 × 1 32 3 4 ⎛ ⎜ ⎜ ⎜ ⎝ ⎞ ⎟ ⎠ 2 × = V pipe 1.60 ft s ⋅ =...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern