{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Problem 4.20 - 2 ⋅ = V feeder 10 ft s ⋅ 10 × 1 8 1 ⎛...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Problem 4.20 [Difficulty: 1] Given: Data on flow through nozzles Find: Average velocity in head feeder; flow rate Solution: Basic equation CS V A ( ) 0 = Assumptions: 1) Steady flow 2) Incompressible flow 3) Uniform flow Then for the nozzle flow CS V A ( ) V feeder A feeder 10 V nozzle A nozzle + = 0 = Hence V feeder V nozzle 10 A nozzle A feeder = V nozzle 10 D nozzle D feeder 2
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 ⋅ = V feeder 10 ft s ⋅ 10 × 1 8 1 ⎛ ⎜ ⎝ ⎞ ⎠ 2 × = V feeder 1.56 ft s ⋅ = The flow rate is Q V feeder A feeder ⋅ = V feeder π D feeder 2 ⋅ 4 ⋅ = Q 1.56 ft s ⋅ π 4 × 1 in ⋅ 1 ft ⋅ 12 in ⋅ × ⎛ ⎝ ⎞ ⎠ 2 × 7.48 gal ⋅ 1 ft 3 ⋅ × 60 s ⋅ 1 min ⋅ × = Q 3.82 gpm ⋅ =...
View Full Document

{[ snackBarMessage ]}