Problem 4.24
[Difficulty: 1]
Given:
Data on flow through box
Find:
Velocity at station 3
Solution:
Basic equation
CS
V
→
A
→
⋅
(
)
∑
0
=
Assumptions:
1) Steady flow
2) Incompressible flow 3) Uniform flow
Then for the box
CS
V
→
A
→
⋅
(
)
∑
V
1
−
A
1
⋅
V
2
A
2
⋅
+
V
3
A
3
⋅
+
=
0
=
Note that the vectors indicate that flow is in at location 1 and out at location 2; we assume outflow at location 3
Hence
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 Fall '07
 Lear
 Fluid Dynamics, Fluid Mechanics, Zagreb, Incompressible Flow, vy, 0.5 ft

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