Problem 4.27 [Difficulty: 1] Given: Data on filling of glass carboy Find: Time to fill Solution: We can treat this as an unsteady problem if we choose the CS as the entire carboy Basic equation t M CV ∂ ∂ CS ρ V → ⋅ A → ⋅ () ∑ +0 = Assumptions: 1) Incompressible flow 2) Uniform flow Given data: Q 3 gpm ⋅ = D1 5 i n ⋅ = h2 f t ⋅ = Hence t
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.