Problem 4.30

# Problem 4.30 - − = where A is the basement area and dh/dt...

This preview shows page 1. Sign up to view the full content.

Problem 4.30 [Difficulty: 1] Given: Data on filling of a basement during a storm Find: Flow rate of storm into basement Solution: This is an unsteady problem if we choose the CS as the entire basement Basic equation t M CV CS ρ V A () + 0 = Assumptions: 1) Incompressible flow Given data: Q pump 27.5 gpm = dh dt 4 in hr = A3 0 f t 20 ft = Hence t M CV ρ A dh dt = CS ρ V A () = ρ Q storm ρ Q
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: − = where A is the basement area and dh/dt is the rate at which the height of water in the basement changes. Q storm Q pump A dh dt ⋅ − = or Q storm 27.5 gal min ⋅ 30 ft ⋅ 20 × ft ⋅ 4 12 ft hr ⋅ ⎛ ⎝ ⎞ ⎠ × 7.48 gal ⋅ ft 3 × 1 hr ⋅ 60 min ⋅ × − = Data on gals from Table G.2 Q storm 2.57 gpm ⋅ =...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online