Problem 4.39 - min V min x h w d = 2 V min h V min h 2 2 h...

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Problem 4.39 [Difficulty: 2] Given: Data on flow at inlet and outlet of channel Find: Find u max Solution: 0 = CS A d V r r ρ Basic equation Assumptions: 1) Steady flow 2) Incompressible flow Evaluating at inlet and exit U w h 0 h x V exit x ()w d + 0 = Here we have V exit V max V max V min () x h = But we also have V max 2V min = Hence V exit 2V min V min x h = 0 h x V exit x ()w d 0 h x 2V
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Unformatted text preview: min V min x h w d = 2 V min h V min h 2 2 h w = 3 2 V min h w = 3 2 V min h w U w h = V min 2 3 U = Hence V min 2 3 7.5 m s = V min 5.00 m s =...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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