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Problem 4.64
[Difficulty: 1]
Given:
Fully developed flow in pipe
Find:
Why pressure drops if momentum is constant
Solution:
Basic equation: Momentum flux in x direction
Assumptions:
1) Steady flow
2) Fully developed flow
Hence
F
x
∆
p
L
τ
w
A
s
⋅
−
=
0
=
∆
pL
τ
w
⋅
A
s
⋅
=
where
∆
p is the pressure drop over length L,
τ
w
is the wall friction and As is the pipe surface area
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 Fall '07
 Lear
 Fluid Mechanics, Flux

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