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Problem 4.65
[Difficulty: 2]
Given:
Data on flow and system geometry
Find:
Force required to hold plug
Solution:
Basic equation:
The given data is
D
1
0.25 m
⋅
=
D
2
0.2 m
⋅
=
Q
1.5
m
3
s
⋅
=
p
1
3500 kPa
⋅
=
ρ
999
kg
m
3
⋅
=
Then
A
1
π
D
1
2
⋅
4
=
A
1
0.0491 m
2
=
V
1
Q
A
1
=
V
1
30.6
m
s
=
A
2
π
4
D
1
2
D
2
2
−
⎛
⎝
⎞
⎠
⋅
=
A
2
0.0177 m
2
=
V
2
Q
A
2
=
V
2
84.9
m
s
=
Applying the basic equation
F
−
p
1
A
2
⋅
+
p
2
A
2
⋅
−
0V
1
ρ
−
V
1
⋅
A
1
⋅
()
⋅
+
V
2
ρ
V
2
⋅
A
2
⋅
⋅
+
=
and
p
2
0
=
(gage)
Hence
Fp
1
A
1
⋅
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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