Problem 4.71 - Problem 4.71 [Difficulty: 3] Given: Water...

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Problem 4.71 [Difficulty: 3] Given: Water tank attached to mass Find: Whether tank starts moving; Mass to just hold in place Solution: Basic equation: Momentum flux in x direction for the tank Assumptions: 1) Steady flow 2) Incompressible flow 3) Atmospheric pressure at exit 4) Uniform flow Hence R x V cos θ () ρ VA = ρ V 2 π D 2 4 cos θ = We need to find V. We could use the Bernoulli equation, but here it is known that V2 g h = where h = 2 m is the height of fluid in the tank V 2 9.81 × m s 2 2 × m = V 6.26 m s = Hence R x 1000 kg m 3 6.26 m s 2 × π 4 × 0.05 m 2 × cos 60 deg × = R x 38.5 N = This force is equal to the tension T in the wire
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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