Problem 4.71[Difficulty: 3]Given:Water tank attached to massFind:Whether tank starts moving; Mass to just hold in placeSolution:Basic equation: Momentum flux in x direction for the tankAssumptions: 1) Steady flow 2) Incompressible flow 3) Atmospheric pressure at exit 4) Uniform flowHenceRxV cosθ()⋅ρ⋅VA⋅⋅=ρV2⋅πD2⋅4⋅cosθ⋅=We need to find V. We could use the Bernoulli equation, but here it is known thatV2g⋅h⋅=where h = 2 m is theheight of fluid in the tankV29.81×ms2⋅2×m⋅=V6.26ms=HenceRx1000kgm3⋅6.26ms⋅⎛⎝⎞⎠2×π4×0.05 m⋅2×cos 60 deg⋅×=Rx38.5 N=This force is equal to the tension T in the wire
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.