Problem 4.118 - 2 ⋅ ρ g ⋅ H ⋅ − = V 3 V 2 2 2 g ⋅ H ⋅ = V 3 19.3 m s = For the plate there is no force along the plate(x momentum as

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Problem *4.118 [Difficulty: 3] Given: Nozzle flow striking inclined plate Find: Mimimum gage pressure Solution: Basic equations: Bernoulli and y momentum p ρ V 2 2 + gz + const = The given data is ρ 999 kg m 3 = q 1200 L sm = W8 0 m m = h 0.25 m = w2 0 m m = H 7.5 m = θ 30 deg = For the exit velocity and nozzle velocity V 2 q W = V 2 15.0 m s = V 1 V 2 w W = V 1 3.75 m s = Then from Bernoulli p 1 ρ 2 V 1 2 + p atm ρ 2 V 2 2 + = or p 1 ρ 2 V 2 2 V 1 2 ρ g h = p 1 103 kPa = (gage) Applying Bernoulli between 2 and the plate (state 3) p atm ρ 2 V 2 2 + p atm
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Unformatted text preview: 2 ⋅ + ρ g ⋅ H ⋅ − = V 3 V 2 2 2 g ⋅ H ⋅ + = V 3 19.3 m s = For the plate there is no force along the plate (x momentum) as there is no friction. For the force normal to the plate (y momentum) we have R y V 3 − cos θ ( ) ⋅ ρ − V 3 ⋅ A 3 ⋅ ( ) ⋅ = V 3 − cos θ ( ) ⋅ ρ − q ⋅ ( ) ⋅ = R y V 3 cos θ ( ) ⋅ ρ ⋅ q ⋅ = R y 20.0 kN m ⋅ =...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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