Unformatted text preview: ⋅ M c v ⋅ dT dt ⋅ + u m exit ⋅ + p ρ m exit ⋅ + = dT dt m exit p ⋅ M c v ⋅ ρ ⋅ − = But M ρ V ⋅ = (where V is volume) so dT dt m exit p ⋅ V c v ⋅ ρ 2 ⋅ − = For air ρ p R air T ⋅ = ρ 500 10 3 × N m 2 ⋅ kg K ⋅ 286.9 N ⋅ m ⋅ × 1 20 273 + ( ) K ⋅ × = ρ 5.95 kg m 3 = Hence dT dt 0.01 − kg s ⋅ 500 × 10 3 × N m 2 ⋅ 1 100 L ⋅ × L 10 3 − m 3 ⋅ × kg K ⋅ 717.4 N ⋅ m ⋅ × m 3 5.95 kg ⋅ ⎛ ⎜ ⎝ ⎞ ⎠ 2 × = 1.97 − K s ⋅ = 1.97 − C s ⋅ =...
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 Fall '07
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 Dynamics, Fluid Mechanics, Thermodynamics, Entropy, dt, mexit

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