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Unformatted text preview: V 400 nmi hr 6080 ft nmi hr 3600 s V 675.56 ft s v 2500 ft min min 60 s v 41.67 ft s Therefore: u 675.56 ft s 2 41.67 ft s 2 u 674.27 ft s So the rate of change of temperature through the cold front is: δ T x 0.7 Δ °F min s 674.27 ft min 60 s 5280 ft mi δ T x 0.0914 Δ °F mi Rate of temperature change with respect to horizontal distance through cold front....
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
- Fall '07
- Fluid Mechanics