Problem 5.64 - Problem 5.64 [Difficulty: 3] Steady inviscid...

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Problem 5.64 [Difficulty: 3] Given: Steady inviscid flow over a circular cylinder of radius R Find: a prmax 0.372 U 2 R Solution: We will apply the particle acceleration definition to the velocity field  t V V V Dt V D a p Governing Equation: (Particle Accleration) Assumptions: (1) Steady flow (2) Inviscid flow (3) No flow in z-direction, velocity is not a function of z V r V r V V a r p Based on the above assumptions the particle acceleration reduces to: and the components are: a pr V r r V r V θ r θ V r V θ 2 r a p θ V r r V θ V θ r θ V θ V r V θ r When θ = π : V r U 1 R r 2 V θ 0 r V r U 2 R 2 r 3 2 U R 2 r 3 θ V r 0 r V θ 0 θ V θ 0 So the accelerations are: a pr U 1 R r
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Problem 5.64 - Problem 5.64 [Difficulty: 3] Steady inviscid...

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