Problem 5.72 - y d A 2 x d 2 x a 2 y c 2 y d 2 x b 2 x c 2...

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Circulation about the unit square shown above. Problem 5.72 [Difficulty: 2] Given: Velocity field for flow in a rectangular corner as in Example 5.8. Find: Solution: We will apply the definition of circulation to the given velocity field. s d V Governing Equation: (Definition of circulation) da cd bc ab s d V s d V s d V s d V From the definition of circulation we break up the integral:    Aydy Axdx j dy i dx j Ay i Ax s d V ˆ ˆ ˆ ˆ The integrand is equal to: Therefore, the circulation is equal to: Γ x a x d x Ax d y d y c y A y d x c x b x Ax d y b y a y A
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Unformatted text preview: y d A 2 x d 2 x a 2 y c 2 y d 2 x b 2 x c 2 y a 2 y b 2 Γ 1 2 0.3 1 s 2 2 1 2 2 2 1 2 1 2 2 2 1 2 2 2 m 2 Γ m 2 s This result is to be expected since the flow is irrotational and by Stokes' theorem, the circulation is equal to the curl of the velocity over the bounded area (Eqn. 5.18)....
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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