Problem 5.102 - Problem 5.102 [Difficulty: 3] New Eq. 5.37:...

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Problem 5.102 [Difficulty: 3] New Eq. 5.37: N = 4 x = 0.333 Eq. 5.34 (LHS) (RHS) 1.000 0.000 0.000 0.000 3 -1.000 1.333 0.000 0.000 0.18519 0.000 -1.000 1.333 0.000 0.51852 0.000 0.000 -1.000 1.333 1 x Inverse Matrix Result Exact Error 0.000 1.000 0.000 0.000 0.000 3.000 3.000 0.000 0.333 0.750 0.750 0.000 0.000 2.389 2.222 0.007 0.667 0.563 0.563 0.750 0.000 2.181 1.889 0.021 1.000 0.422 0.422 0.563 0.750 2.385 2.000 0.037 0.256 N = 8 x = 0.143 Eq. 5.34 (LHS) (RHS) 1.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 3 -1.000 1.143 0.000 0.000 0.000 0.000 0.000 0.000 0.02624 0.000 -1.000 1.143 0.000 0.000 0.000 0.000 0.000 0.06414 0.000 0.000 -1.000 1.143 0.000 0.000 0.000 0.000 0.1137 0.000 0.000 0.000 -1.000 1.143 0.000 0.000 0.000 0.17493 0.000 0.000 0.000 0.000 -1.000 1.143 0.000 0.000 0.24781 0.000 0.000 0.000 0.000 0.000 -1.000 1.143 0.000 0.33236 0.000 0.000 0.000 0.000 0.000 0.000 -1.000 1.143 0.42857     i i i i x x x u x u 2 1 2 1
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Inverse Matrix x 1 2 3 4 5 6 7 8 Result Exact Error 0.000 1.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 3.000 3.000 0.000 0.143 0.875 0.875 0.000 0.000 0.000 0.000 0.000 0.000 2.648 2.612 0.000 0.286 0.766 0.766 0.875 0.000 0.000 0.000 0.000 0.000
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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Problem 5.102 - Problem 5.102 [Difficulty: 3] New Eq. 5.37:...

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