Problem 5.103

# Problem 5.103 - Problem 5.103[Difficulty 3 Equation of...

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Problem 5.103 [Difficulty: 3] Equation of motion: New Eq. 5.37: N = 4 A = 0.0025 m 2 t 0.333 = 0.5 mm Eq. 5.34 (LHS) (RHS) = 0.45 N.s/m 2 1.000 0.000 0.000 0.000 1 M = 3 kg -1.000 1.250 0.000 0.000 0 k = 0.75 s -1 0.000 -1.000 1.250 0.000 0 0.000 0.000 -1.000 1.250 0 t Inverse Matrix Result Exact Error 0.000 1.000 0.000 0.000 0.000 1.000 1.000 0.0E+00 0.333 0.800 0.800 0.000 0.000 0.800 0.779 1.1E-04 0.667 0.640 0.640 0.800 0.000 0.640 0.607 2.8E-04 1.000 0.512 0.512 0.640 0.800 0.512 0.472 3.9E-04 0.028 N = 8 t 0.143 Eq. 5.34 (LHS) (RHS) 1.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 1 -1.000 1.107 0.000 0.000 0.000 0.000 0.000 0.000 0 0.000 -1.000 1.107 0.000 0.000 0.000 0.000 0.000 0 0.000 0.000 -1.000 1.107 0.000 0.000 0.000 0.000 0 0.000 0.000 0.000 -1.000 1.107 0.000 0.000 0.000 0 0.000 0.000 0.000 0.000 -1.000 1.107 0.000 0.000 0 0.000 0.000 0.000 0.000 0.000 -1.000 1.107 0.000 0 0.000 0.000 0.000 0.000 0.000 0.000 -1.000 1.107 0 0 1 1 i i u t k u u A A dy du dt du M 0 u M A dt du 0 u k dt du

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Inverse Matrix t 1 2 3 4 5 6 7 8 Result Exact Error 0.000 1.000 0.000 0.000 0.000 0.000 0.000 0.000 0.000 1.000 1.000 0.0E+00 0.143 0.903 0.903 0.000
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Problem 5.103 - Problem 5.103[Difficulty 3 Equation of...

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