Problem 6.11 - Problem 6.11[Difficulty 2 Given Velocity...

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Problem 6.11 [Difficulty: 2] Given: Velocity field Find: Expression for pressure gradient; plot; evaluate pressure at outlet Solution: Basic equations Given data U 15 m s = L 5 m = p in 100 kPa = ρ 1250 kg m 3 = Here u x ( ) U 1 x L = u 0 ( ) 15 m s = u L ( ) 0 m s = The x momentum becomes ρ u x u d d ρ a a = x p d d = Hence a x x ( ) u x ( ) x u x ( ) = a x x ( ) U 2 x L 1 L = The pressure gradient is then dp dx ρ
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