Problem 6.11
[Difficulty: 2]
Given:
Velocity field
Find:
Expression for pressure gradient; plot; evaluate pressure at outlet
Solution:
Basic equations
Given data
U1
5
m
s
⋅
=
L5
m
⋅
=
p
in
100 kPa
⋅
=
ρ
1250
kg
m
3
⋅
=
Here
ux
()
U 1
x
L
−
⎛
⎝
⎞
⎠
⋅
=
u0
() 1
5
m
s
=
uL
() 0
m
s
=
The x momentum becomes
ρ
u
⋅
x
u
d
d
⋅
ρ
a
a
⋅
=
x
p
d
d
−
=
Hence
a
x
x
x
∂
∂
⋅
=
a
x
x
U
2
x
L
1
−
⎛
⎝
⎞
⎠
⋅
L
=
The pressure gradient is then
dp
dx
ρ
−
U
2
L
⋅
x
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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