Problem 6.11 - Problem 6.11[Difficulty 2 Given Velocity...

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Problem 6.11 [Difficulty: 2] Given: Velocity field Find: Expression for pressure gradient; plot; evaluate pressure at outlet Solution: Basic equations Given data U1 5 m s = L5 m = p in 100 kPa = ρ 1250 kg m 3 = Here ux () U 1 x L = u0 () 1 5 m s = uL () 0 m s = The x momentum becomes ρ u x u d d ρ a a = x p d d = Hence a x x x = a x x U 2 x L 1 L = The pressure gradient is then dp dx ρ U 2 L x
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.

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