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Unformatted text preview: p x ( ) p in ρ x x a x x ( ) ⌠ ⎮ ⌡ d ⋅ − = p x ( ) p in U 2 ρ ⋅ e 2 x ⋅ L − 1 − ⎛ ⎜ ⎝ ⎞ ⎠ ⋅ 2 − = Hence p L ( ) p in U 2 ρ ⋅ e 2 − 1 − ( ) ⋅ 2 − = p L ( ) 206 kPa ⋅ = 0.5 1 1.5 2 50 100 150 200 x (m) dp/dx (kPa/m) 0.5 1 1.5 2 200 − 150 − 100 − 50 − x (m) ax (m/s2)...
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This note was uploaded on 10/19/2011 for the course EGN 3353C taught by Professor Lear during the Fall '07 term at University of Florida.
 Fall '07
 Lear
 Fluid Mechanics

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