# HW1 - Solutions to HW1 MTH 540 2.5 a A B A B = A B B = A S...

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8 Solutions to HW1: MTH 540 2.5 a. A S A B B A B A B A = = = ) ( ) ( ) ( . b. A A B B B A B B A B = = = ) ( ) ( ) ( ) ( . c. = = ) ( ) ( ) ( B B A B A B A 0 / . The result follows from part a. d. ) ( ) ( B B A B A B = = 0 / . The result follows from part b. 2.6 A = {(1,2), (2,2), (3,2), (4,2), (5,2), (6,2), (1,4), (2,4), (3,4), (4,4), (5,4), (6,4), (1,6), (2,6), (3,6), (4,6), (5,6), (6,6)} C = {(2,2), (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6)} A B = {(2,2), (4,2), (6,2), (2,4), (4,4), (6,4), (2,6), (4,6), (6,6)} B A = {(1,2), (3,2), (5,2), (1,4), (3,4), (5,4), (1,6), (3,6), (5,6)} B A = everything but {(1,2), (1,4), (1,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6)} A C A = 2.11 a. Since P ( S ) = P (E 1 ) + … + P (E 5 ) = 1, 1 = .15 + .15 + .40 + 3 P (E 5 ). So, P (E 5 ) = .10 and P (E 4 ) = .20. b.

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## This note was uploaded on 10/19/2011 for the course MATH MTH 540 taught by Professor Smith during the Fall '00 term at University of Alberta.

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HW1 - Solutions to HW1 MTH 540 2.5 a A B A B = A B B = A S...

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