Unformatted text preview: u = u + t t Write the problem as u = u t + 1. Set y = u/t which implies u = ty + y Thus we get ty + y = y + 1. This equation is separable so we separate and integrate Z dy = Z dt t So y = ln( t ) + C and ﬁnally u = t (ln( t ) + C ) ....
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- Fall '05
- Math, Trigraph, Boundary value problem, ty