TOM453 MIDTERM CS

# TOM453 MIDTERM CS - 81 note grand total always 81 on any...

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customer location(x,y) weight(demand) 1 4, 4 3 2 4, 11 2 3 7, 2 2 4 11, 11 4 5 14, 7 _1_ median (SUM/2) 12 12/2 = 6. plot 14 | 12 | 2 . (7, 11) . 4 10 | 8 | (7, 7) . 5 6 | 4 | 1 . . 3 2 |__,__,__,__,__,__,__,__ 2 4 6 8 10 12 14 left to right (from bot om: right to left) customers xi wi ∑wi 1 4 3 3 2 4 2 5 3 7 2 7 7 4 11 4 5 5 14 1 1 bot om to top (from bot om: top to bot om) customers yi wi ∑wi 3 2 2 2 1 4 3 5 5 7 1 6 2 11 2 6 4 11 4 4 total weighted distance from (7, 7) customer distance weight weighted dist. 1 (4, 4) 6 3 18 2 (4, 11) 7 2 14 3 (7, 2) 5 2 10 4 (11, 11) 8 4 32 5 (14, 7) 7 1 _7_ grand total =
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Unformatted text preview: 81 note: grand total always 81 on any optimal XCG = [4(3)+4(2)+7(2)+11(4)+14(1)/12] = 7.67 YCG = [4(3)+11(2)+2(2)+11(4)+7(1)/12] = 7.42 customer location weight distance__________ 1 4, 4 3 √(7.67–4) 2 + (7.42–4) 2 _ 2 4, 11 2 √(7.67–4) 2 + (7.42–11) 2 3 7, 2 2 √(7.67–7) 2 + (7.42–2) 2 __ 4 11, 11 4 √(7.67–11) 2 + (7.42–11) 2 5 14, 7 _1_ √(7.67–14) 2 + (7.42–7) 2...
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## This note was uploaded on 10/19/2011 for the course TOM 453 taught by Professor Kumar during the Spring '11 term at Cal Poly Pomona.

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