Waiting Line - 1. [Infinite source, single channel] = 3/day...

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Unformatted text preview: 1. [Infinite source, single channel] = 3/day = 4/day a. customers 25 . 2 ) 3 4 ( 4 3 ) ( L 2 2 q = = = [Alternate solution, using infinite queuing table:] , 75 . r = = M = 1. From table 184, L q = 2.25 customers b. % 75 or , 75 . 4 3 = = c. Percentage of time idle is 1 p = 25%. Thus 25%(8) = 2 hours. d. P(L s 2) = 1 [P o + P 1 ] = 1 [.25 + .25(.75)] = .5625 3. = 30/hr. Single Channel = 40/hr. a. line in customers 25 . 2 ) 30 40 ( 40 30 ) ( L 2 2 q = = = minutes 5 . 4 . hrs 075 . 30 25 . 2 L W q q = = + = W S = W q +1/ = 4.5 + 1.5 = 6 minutes b. 25 . 40 30 1 1 P = = = c. L q = 2.25 customers (see part a.) Solutions (continued) 4. [Infinite source, multiple channel] = .45 requests/hr. = .50 request/hr. M = 2 ambulances a. % 45 45 . ) 50 (. 2 45 . or M = = = b. . 80 . 50 , 45 ....
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This document was uploaded on 10/21/2011.

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Waiting Line - 1. [Infinite source, single channel] = 3/day...

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