Unformatted text preview: and the current i(0) = i(0+) = 12/3 = 4A For t > 0, the switch is open and only the inductor and 2 and 6 ohm resistors remain. Thus, L = 4 and R = 8 L/R = 1/2 Thus: i ( t ) = 4 e − t /(1/2) = 4 e − 2 t And v ( t ) = L di dt = 4( − 2)(4) e − 2 t = − 32 e − 2 t +! ! " ! #$ % & ’ ( ) ! *"+ ,....
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 Fall '10
 DrSharlenekatz
 Resistor, Electrical resistance, Electrical impedance, ________________________ ECE

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