240_quiz7a - 2 si 4 6 i 4 i − 2 8 s i − 2 = i 2 s 6 4 8...

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Name ___________________________ ECE 240 – Quiz #7 April 1, 2010 Write the differential equation for the current, i. DO NOT SOLVE this equation. If we define the mesh current in the top mesh to be 2 going clockwise, and the mesh current in the bottom loop to be “i” going clockwise, writing KVL around the bottom loop we have:
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Unformatted text preview: 2 si + 4 + 6 i + 4 i − 2 ( ) + 8 s i − 2 ( ) = i 2 s + 6 + 4 + 8 s ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = − 4 + 8 + 16 s = 4 + 16 s i s 2 + 5 s + 4 ⎡ ⎣ ⎤ ⎦ = 2 s + 8 ⇒ ′′ i + 5 ′ i + 4 i = 8 +-!" # ! $ ! #% &’( * !+ ,...
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This note was uploaded on 10/19/2011 for the course ECE 240 taught by Professor Drsharlenekatz during the Fall '10 term at CSU Northridge.

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