240_quiz8a - 54.3 ° ( ) V = − j 400 20 − j 20 10 + j...

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Name ___________________________ ECE 240 – Quiz #8 April 22, 2010 Assume the circuit is in steady state. Find: a. i(t) b. v(t) Z = 10 + j 12 + 20 || j 20 = 10 + j 12 j 400 20 j 20 = 20.1 5.7 ° I = 10 60 ° 20.1 5.7 ° = 0.498 54.3 ° i ( t ) = 0.498 cos 4 t +
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Unformatted text preview: 54.3 ° ( ) V = − j 400 20 − j 20 10 + j 12 − j 400 20 − j 20 10 60 ° = 7.04 9.3 ° ⇒ v ( t ) = 7.04 cos 4 t + 9.3 ° ( ) +-!" $%&’() * +",-!" ! ./ 0" ! * 1 2 !34" 5 6...
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This note was uploaded on 10/19/2011 for the course ECE 240 taught by Professor Drsharlenekatz during the Fall '10 term at CSU Northridge.

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