# ict02 - Version 017/AABAB ict 02 Turner(92510 Ax = 2.4 A y...

This preview shows pages 1–2. Sign up to view the full content.

Version 017/AABAB – ict 02 – Turner – (92510) 1 This print-out should have 2 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Vector vector A has components A x = 2 . 4 , A y = 5 , A z = 1 . 6 , while vector vector B has components B x = 6 . 7 , B y = 3 . 2 , B z = 4 . 1 . What is the angle θ AB between these vec- tors? (Answer between 0 and 180 .) 1. 121.416 2. 156.52 3. 111.897 4. 132.968 5. 89.7192 6. 97.2163 7. 115.127 8. 84.0386 9. 93.1496 10. 137.806 Correct answer: 121 . 416 . Explanation: bardbl vector A bardbl = radicalBig A 2 x + A 2 y + A 2 z = radicalBig ( 2 . 4) 2 + 5 2 + 1 . 6 2 = 5 . 77235 and bardbl vector B bardbl = radicalBig B 2 x + B 2 y + B 2 z = radicalBig 6 . 7 2 + ( 3 . 2) 2 + 4 . 1 2 = 8 . 48175 , so using vector A · vector B = A x B x + A y B y + A z B z = ( 2 . 4) 6 . 7 + 5 ( 3 . 2) + 1 . 6 (4 . 1) = 25 . 52 , cos θ AB = vector A · vector B bardbl vector A bardbl bardbl vector B bardbl = 25 . 52 (5 . 77235) (8 . 48175) = 0 . 521246 θ AB = arccos( 0 . 521246) = 121 . 416 . Two vectors can define a plane. When these two vectors are plotted in this plane, we have A B 121 . 416 002 10.0 points Two airplanes leave an airport at the same time. The velocity of the first airplane is 680 m / h at a heading of 57 . 7 . The velocity

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern