ict02 - Version 017/AABAB – ict 02 – Turner – (92510)...

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Unformatted text preview: Version 017/AABAB – ict 02 – Turner – (92510) 1 This print-out should have 2 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Vector vector A has components A x = − 2 . 4 , A y = 5 , A z = 1 . 6 , while vector vector B has components B x = 6 . 7 , B y = − 3 . 2 , B z = 4 . 1 . What is the angle θ AB between these vec- tors? (Answer between 0 ◦ and 180 ◦ .) 1. 121.416 2. 156.52 3. 111.897 4. 132.968 5. 89.7192 6. 97.2163 7. 115.127 8. 84.0386 9. 93.1496 10. 137.806 Correct answer: 121 . 416 ◦ . Explanation: bardbl vector A bardbl = radicalBig A 2 x + A 2 y + A 2 z = radicalBig ( − 2 . 4) 2 + 5 2 + 1 . 6 2 = 5 . 77235 and bardbl vector B bardbl = radicalBig B 2 x + B 2 y + B 2 z = radicalBig 6 . 7 2 + ( − 3 . 2) 2 + 4 . 1 2 = 8 . 48175 , so using vector A · vector B = A x B x + A y B y + A z B z = ( − 2 . 4) 6 . 7 + 5 ( − 3 . 2) + 1 . 6(4 . 1) = − 25 . 52 , cos θ AB = vector A ·...
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This note was uploaded on 10/20/2011 for the course PHYSICS 302K taught by Professor Irenepolycarpou during the Summer '09 term at University of Texas.

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ict02 - Version 017/AABAB – ict 02 – Turner – (92510)...

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