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Unformatted text preview: alexander (jra2623) – oldhomework 01 – Turner – (92510)
This printout should have 4 questions.
Multiplechoice questions may continue on
the next column or page – ﬁnd all choices
before answering. 1. Yes; it weighs about 4.5 lbs. ρ2
ρ1 R2
R1 M1
=
M2 ρ1
ρ2 R2
R1 3 4.
001 10.0 points
In one scene in the movie The Godfather II,
a solid gold phone is passed around a large
table for everyone to see. Suppose the volume
of gold in the phone were equal to the volume
of a 10centimeter cube of gold. The density
of gold is 19,300 kg/m3 .
Could such a phone be casually passed
around a table from hand to hand? What
is the weight of the phone? 1 kg of mass is
about 2.2 lb. M1
=
M2 2 3. M1
5.
=
M2 ρ2
ρ1 R1
R2 2 M1
6.
=
M2 ρ1
ρ2 R1
R2 3 M1
=
M2
M1
=
8.
M2
M1
=
9.
M2 ρ2
ρ1
ρ2
ρ1
ρ1
ρ2 R1
R2
R1
R2
R1
R2 3 M1
=
M2 ρ1
ρ2 R2
R1 1 2 7. 2. Yes; it weighs about 9 lbs. 10. 3. No; it weighs about 90 lbs. correct Explanation:
m
ρ=
, so
V 4. No; it weighs about 45 lbs. correct
Explanation:
One cubic meter of gold has a mass of about
20,000 kg, which is roughly 45,000 pounds.
A ten centimeter cube of gold is about 45
pounds; it would be diﬃcult to pass around
this phone.
m = ρ V = (19300 kg/m3 )(10 cm)3
1m
100 cm × 3 2.2 lb
1 kg = 42.46 lbs . M1
=
M2 M1
=
M2 ρ2
ρ1 R2
R1 M1
=
2.
M2 ρ1
ρ2 R1
R2 2 A1
2.
=
A2 3 R1
R2
R2
R1 3 2 A1
R2
=π
A2
R1
R2
A1
=
4.
A2
R1
3. 3 1. ρ2 = 3
ρ1 R1
3.
ρ2 R2 003 (part 2 of 2) 10.0 points
A1
of the circular areas
What is the ratio
A2
deﬁned by the two equators?
A1
1.
=π
A2 002 (part 1 of 2) 10.0 points
Consider two planets with uniform mass distributions. The mass density and the radius
of planet 1 are ρ1 and R1 , respectively, and
those of planet 2 are ρ2 and R2
M1
What is the ratio
of their masses?
M2 4
3
π R1
3
4
3
π R2
3 ρ1 5. A1
=
A2 A1
=π
6.
A2 R1
R2
R1
R2 3 2 alexander (jra2623) – oldhomework 01 – Turner – (92510) 7. A1
=
A2 8. A1
=π
A2 A1
9.
=
A2
A1
=
10.
A2 R2
R1 2 3 R2
R1
R1
R2
R1
R2 2 correct Explanation:
A = π r 2 , so
2
2
A1
R1
πR1
=
2 = R2 .
A2
πR2
2 004 10.0 points
The distance between the sun and the Earth
is about 1.5184 × 1011 m.
Express this distance in kilometers.
1. None of these
2. 1.5184 × 108 km correct
3. 1.5184 × 109 km
4. 1.5184 × 106 km
5. 1.5184 × 1010 km
6. 1.5184 × 1011 km
7. 1.5184 × 107 km
Explanation:
1 km = 1 × 103 m , so d = 1.5184 × 1011 m ·
= 1.5184 × 108 km . 1 km
1 × 103 m 2 ...
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 Summer '08
 Kaplunovsky
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