This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: alexander (jra2623) oldhomework 04 Turner (92510) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Consider the following set of equations, where s , s , x and r have units of length, t has units of time, v has units of velocity, g and a have units of acceleration, and k is dimensionless. Which one is dimensionally incorrect ? 1. t = k radicalbigg s g + a v correct 2. s = s + v t + v 2 a 3. t = v a + x v 4. a = g + k v t + v 2 s 5. v 2 = 2 a s + k s v t Explanation: For an equation to be dimensionally cor- rect, all its terms must have the same units. t = v a + x v [ t ] = T bracketleftBig v a bracketrightBig + bracketleftBig x v bracketrightBig = L T- 1 L T- 2 + L L T- 1 = T + T = T It is consistent. a = g + k v t + v 2 s [ a ] = L T- 2 bracketleftbigg g + kv t + v 2 s bracketrightbigg = L T- 2 + L T- 1 T + L 2 T- 2 L = L T- 2 It is also consistent. t = k radicalbigg s g + a v [ t ] = T bracketleftbigg k radicalbigg s g + a v bracketrightbigg = radicalbigg L L T- 2 + L T- 2 L T- 1 = T + T- 1 This is not dimensionally consistent....
View Full Document
- Summer '08