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Unformatted text preview: alexander (jra2623) oldhomework 15 Turner (92510) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points Tom has a mass of 72 . 9 kg and Sally has a mass of 51 . 3 kg. Tom and Sally are standing 21 . 7 m apart on a massless dance floor. Sally looks up and she sees Tom. She feels an attraction. If the attraction is gravitation, find its mag nitude. Assume both can be replaced by spherical masses and that the gravitational constant is 6 . 67259 10 11 N m 2 / kg 2 . Correct answer: 5 . 29932 10 10 N. Explanation: Let : m T = 72 . 9 kg , m S = 51 . 3 kg , d = 21 . 7 m , and G = 6 . 67259 10 11 N m 2 / kg 2 . By Newtons universal law of gravitation, F = G m T m S d 2 = (6 . 67259 10 11 N m 2 / kg 2 ) (72 . 9 kg) (51 . 3 kg) (21 . 7 m) 2 = 5 . 29932 10 10 N . 002 (part 1 of 4) 10.0 points Calculate the force of gravity on a 130 kg person at the surface of the Earth. The accel eration of gravity is 9.8 m/s 2 . Correct answer: 1274 N. Explanation: Let : m = 130 kg , and g = 9 . 8 m / s 2 . W = mg = (130 kg) (9 . 8 m / s 2 ) = 1274 N . 003 (part 2 of 4) 10.0 points What force of gravity exists at two times the Earths radius? Correct answer: 318 . 5 N....
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 Summer '08
 Kaplunovsky
 Mass, Work

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