oldhw 15 - alexander (jra2623) oldhomework 15 Turner...

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Unformatted text preview: alexander (jra2623) oldhomework 15 Turner (92510) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Tom has a mass of 72 . 9 kg and Sally has a mass of 51 . 3 kg. Tom and Sally are standing 21 . 7 m apart on a massless dance floor. Sally looks up and she sees Tom. She feels an attraction. If the attraction is gravitation, find its mag- nitude. Assume both can be replaced by spherical masses and that the gravitational constant is 6 . 67259 10 11 N m 2 / kg 2 . Correct answer: 5 . 29932 10 10 N. Explanation: Let : m T = 72 . 9 kg , m S = 51 . 3 kg , d = 21 . 7 m , and G = 6 . 67259 10 11 N m 2 / kg 2 . By Newtons universal law of gravitation, F = G m T m S d 2 = (6 . 67259 10 11 N m 2 / kg 2 ) (72 . 9 kg) (51 . 3 kg) (21 . 7 m) 2 = 5 . 29932 10 10 N . 002 (part 1 of 4) 10.0 points Calculate the force of gravity on a 130 kg person at the surface of the Earth. The accel- eration of gravity is 9.8 m/s 2 . Correct answer: 1274 N. Explanation: Let : m = 130 kg , and g = 9 . 8 m / s 2 . W = mg = (130 kg) (9 . 8 m / s 2 ) = 1274 N . 003 (part 2 of 4) 10.0 points What force of gravity exists at two times the Earths radius? Correct answer: 318 . 5 N....
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oldhw 15 - alexander (jra2623) oldhomework 15 Turner...

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