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Unformatted text preview: alexander (jra2623) oldhomework 16 Turner (92510) 1 This printout should have 9 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points The planet Mars has a mass of 6 . 1 10 23 kg and radius of 3 . 4 10 6 m. What is the acceleration of an object in free fall near the surface of Mars? The value of the gravitational constant is 6 . 67259 10 11 N m 2 / kg 2 . Correct answer: 3 . 521 m / s 2 . Explanation: Let : M = 6 . 1 10 23 kg , R = 3 . 4 10 6 m , and G = 6 . 67259 10 11 N m 2 / kg 2 . Near the surface of Mars, the gravitation force on an object of mass m is F = G M m R 2 , so the acceleration of an object in free fall is a = F m = G M R 2 = (6 . 67259 10 11 N m 2 / kg 2 ) 6 . 1 10 23 kg (3 . 4 10 6 m) 2 = 3 . 521 m / s 2 . 002 10.0 points An object has a weight W when it is on the surface of a planet of radius R . What will be the gravitational force on the object after it has been moved to a distance of 4 R from the center of the planet? 1. F = 4 W 2. F = 16 W 3. F = 1 4 W 4. F = 1 16 W correct 5. F = W Explanation: On the surface of the planet, W = GM m R 2 . When the object is moved to a distance 4 R from the center of the planet, the gravitational force on it will be F = GM m (4 R ) 2 = GM m 16 R 2 = 1 16 GM m R 2 = 1 16 W ....
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This note was uploaded on 10/20/2011 for the course PHY 302K taught by Professor Kaplunovsky during the Summer '08 term at University of Texas at Austin.
 Summer '08
 Kaplunovsky
 Mass, Work

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