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oldhw 16 - alexander(jra2623 oldhomework 16 Turner(92510...

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alexander (jra2623) – oldhomework 16 – Turner – (92510) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The planet Mars has a mass of 6 . 1 × 10 23 kg and radius of 3 . 4 × 10 6 m. What is the acceleration of an object in free fall near the surface of Mars? The value of the gravitational constant is 6 . 67259 × 10 - 11 N · m 2 / kg 2 . Correct answer: 3 . 521 m / s 2 . Explanation: Let : M = 6 . 1 × 10 23 kg , R = 3 . 4 × 10 6 m , and G = 6 . 67259 × 10 - 11 N · m 2 / kg 2 . Near the surface of Mars, the gravitation force on an object of mass m is F = G M m R 2 , so the acceleration of an object in free fall is a = F m = G M R 2 = (6 . 67259 × 10 - 11 N · m 2 / kg 2 ) × 6 . 1 × 10 23 kg (3 . 4 × 10 6 m) 2 = 3 . 521 m / s 2 . 002 10.0 points An object has a weight W when it is on the surface of a planet of radius R . What will be the gravitational force on the object after it has been moved to a distance of 4 R from the center of the planet? 1. F = 4 W 2. F = 16 W 3. F = 1 4 W 4. F = 1 16 W correct 5. F = W Explanation: On the surface of the planet, W = G M m R 2 . When the object is moved to a distance 4 R from the center of the planet, the gravitational force on it will be F = G M m (4 R ) 2 = G M m 16 R 2 = 1 16 G M m R 2 = 1 16 W . 003 10.0 points Planet X has eight times the diameter and five times the mass of the earth.
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