Homework 2 Solutions _

Homework 2 Solutions _ - 4*3*2 4 P ofeach = = = = 3.42 a....

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Homework 2 Solutions Note: Solutions are incomplete if the solution to the first part is a good representation of the solutions to the other parts. 3.23 Order does not matter, so 2 15 15 15! 105 2 13!2! C = = = ÷ 3.26 a. 10 3 120 C = b. ( 29 2 10 2 90 C = c. 10 1 10 C = 3.31 18 compact cars, 12 midsize cars. 4 cars are chosen from the group of 30 total. Find the probability of getting 2 of each type of car in your sample of 4. We take the number of ways to choose 2 from each group OVER the total number of ways to choose a sample of 4 from a group of 30. 18 12 18! 12! 18*17 12*11 2 2 2!16! 2!10! 2 2 (2 ) .368 30! 30*29*28*27 30 4!26!
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Unformatted text preview: 4*3*2 4 P ofeach = = = = 3.42 a. P(lives > 3 miles from the city | selected) = ( 3 ) ( 3 ) ( ) ( ) ( ) P mi selected P mi P selected P selected P selected = I (indep!) # 3 84 ( 3 ) .56 150 150 people mi P mi = = = = b. P(regularly drives to work) = # 99 .66 150 150 peoplewhodrive = = c. P(does not live >3mi not switch) = ( 29 16 27 ( ) .287 150 P A C P A C + = = = I U d. P(drives switch) = 54 9 ( ) .42 150 P B C + = = I Bonus problem solution will be given at class....
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Homework 2 Solutions _ - 4*3*2 4 P ofeach = = = = 3.42 a....

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