Homework 5 Solutions _

# Homework 5 Solutions _ - = = = 2(1 24.98 23.52 np p σ =-=...

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Homework 5 Solutions Note: Solutions are incomplete if the solution to the first part is a good representation of the solutions to the other parts. 5.36 Let X be the number of items needing repairs. P(repair)=.02. n=1200 P(X≥30) becomes P(X≥29.5) when we make the continuity correction (section 5.2/5.3). 1200(.02) 24 np μ

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Unformatted text preview: = = = 2 (1 ) 24(.98) 23.52 np p σ =-= = , so 4.85 = 29.5 24 29.5) 1 ( 29.5) 1 1 ( 1.13) 4.85 1 (1.13) 1 .8707 .129 ( 2 P X P Z P Z F P X- ≥ = -< = -< = -< ÷ = -= -= Bonus Question: (no points given if the student doesn’t give the right reason) Answer will be given at class....
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## This note was uploaded on 10/20/2011 for the course AMS 310 taught by Professor Mendell during the Spring '08 term at SUNY Stony Brook.

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Homework 5 Solutions _ - = = = 2(1 24.98 23.52 np p σ =-=...

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