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CHEM2211-Morrison-Exam1-2008Fa

CHEM2211-Morrison-Exam1-2008Fa - NAME 8112 first CHEMISTRY...

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Unformatted text preview: NAME 8112}!!! first CHEMISTRY 1211 EXAM I September 11', 21108 Be sure to read each question carefully. Pattie} credit will be assigned where appropriate. Clnltr answers written in en anti in the associated hoses will he raded. Relax and good lucid! 1. 1. (14 points) Draw four isomeric line structures for CgHgN, showing lone pairs: Considering the structures above, an N~H single bond is a I G— | bond 1!]. formed by the overlap of a .3 F3 orbital from N and a —— orbital from H. TUTAL 2. (3 points) Draw a non—cyclic line structure for CHM: that does not contain an spa— hybridized atom and in which no atom possesses a formal charge. _ 2; P '5‘- ;2 no I HTS What is the hybridization of the nitrogen atoms in this structure?r I What is the hybridization of the carbon atom in this structure? 5 f- 1 For HTS. 2 3. {1D points] Complete the Lewis (electron dot) structure of the base cytosine, found in DNA and RNA. Show all lone-pair electrons, and identify the hybridization of the indicated atoms. 9'?th NH2 eflw coasts-LT I of“ {hybridization} fifiofiifioobil‘le' l Celi- "4 we EL‘E‘TR "k . N . Cytosmo #1 - ‘x. as: l 1 PotN'u—TS (hybridization) 2 mm [high ridiz ation] 4. {12 points] Assign formal charges to me atoms in each of the following molecules where the formal charges of the elements are nonzero. In the box below each stmcture, write the symbol for on},r element possessing a formal charge followed by its nonzero formal ollarge {for example: X —1; Y +2). 9H3 .. HBO—hil—g: H3CHN‘NEN: (CH3}2‘_OHBF3 CH3 4m N“ 4 N-H aim O+l 1*" {2-4 W N-l la "Ea-I 5. {It} points} What kind of molecular orbital {oehonding owmtibonding, “Jr-bonding, or n- antiboncling} results when the two atomic orbitals in each pair below interact in the manner indicated? 6‘“ 1o“ lit-INQ- 0 00 + 06 a Hume | 5. {eentmued} [ 8 + 8 M 2 PQINTS | 2. POtHTS r fi. (9 paints) Write in the hex beneath the species en the left-hand side of the following eQuetiene-wheth'er the reactant is amt-acid or a base. E‘. WINE + 1L 0'" UH3GH + H+ {El-1301711 ,e - ”F q.— Tie:4 CHJILIZ-CH3 + net, H3C' {2- CH3 Wiii 15. (continued) Sodium methexide, NaCHgfl. is the eeditttn salt of the eenjugete base of methanol [pig = 15.2}. Cemplete the fellow-ring equilibrium. QUE + enge' Na+ phenul sedi um methoxiee pita = 9.9 II + CHEGH Will the equilibrium fever the right side or the left? '72 I 6: HT '3’. (It) points) Draw reeenanee structures fer the fellewing speeies: 3. {12 peints) Censidet‘ retafien about the C3-C4 bend of 2,4-dimethylhexane. Cerbert 2 is identified en the Newman structure. Cemplete the en'tteture by drawing the Newman projection et‘ the meet stable eenfenner. CH3 1 ez—h eHeHg 4 PGINTE; CH1C..H3 8. [eont'tttuedjl Consider rotation about the C2-C3 bond onA-dltnethylhexan'e. Carbon 1 is identified on the Newman structure. Complete the strueture by drawing the Newman projection of the least stable staggered conformer. (:1 ———e CH; to LH CH'LCH'] 4 POINTS / Consider rotation about the C4-- C5 bond of 2,4-dirnetitylhexane. Carlton 3 is identified en the Newman structure. Cemplete the structure by drawing the Newman projection of the least stable confer-Inert (I’ll: (:3 ——t- CHaeH CH3 H. H HC-Hs IIS 9. {I2 points] Aldosterone is a minereioeortieoid honnone that controls tissue swelling in the body. Circle and name (eg. amine, oerboxyfie acid, and so forth) the six functional groups found in aidosterone. I' 'F'bm‘r anon CER‘RELT CIRCLE l MINT Enrol-t r: oMEtT NHME‘ 4- ETHHL" 3- | sop-renew.- 23'1— enmewsn HEKHN E- 9.9L 4—— ETH‘I‘L— 2,1- BIME‘IHH'L‘ Efifi-ME'THVLETMQHEIHNE M, [“mm In 1* text tserrs L LHLLom-nsma 5h. - f-(‘I-fl- thETH'fiLE—fHHq-Er (p-m‘E'm-flpfim ##fitfiflflfi ...
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